Overs to Balls Converter
Read six-ball overs as balls and rounded decimal overs
The point in 12.4 overs separates overs from balls: it does not mean four tenths of an over. Enter the scorecard’s overs below to convert that count into balls without mixing the two units.
Use six-ball cricket notation, such as 12.4 or 20. Enter at least 0.1; the final ball digit must be 0–5.
Decimal overs are rounded to two places. “Balls Remaining in Over” refers only to the current over, not the rest of the innings. This form converts overs to balls; the guide below explains the reverse calculation.
Enter completed overs and the balls in the unfinished over, separated by a point. For example, 12.4 means 12 overs and 4 balls. Use one ball digit from 0 to 5; whole overs such as 12 are also accepted.
Select Convert to see total balls, decimal overs rounded to two places, and balls left in the current over. Copy results saves the displayed text. Reset clears the input, error message and result.
Formula: Total Balls = (Completed Overs × 6) + Partial Balls
Example: 12.4 overs = (12 × 6) + 4 = 76 total balls
Two meanings for the same-looking number
A scorecard showing 12.4 overs records 12 complete overs and four balls of the next one. Twelve overs contain 72 counted balls; adding four gives 76 balls. For ordinary arithmetic, that is 76 ÷ 6 = 12.666… decimal overs, displayed here as 12.67.
That distinction matters when dividing runs by overs. A fictional 95 runs from 12.4 overs gives 95 × 6 ÷ 76 = 7.50 runs per over. Dividing by the number 12.4 instead gives about 7.66, which answers a different question. For the most accurate manual calculation, keep the whole ball total until the last step.
You may see this described as “base-six” notation. More precisely, the ball digit rolls over after six; the completed-over number is still an ordinary count. You do not need to convert 12 itself from another number base. Read the two parts as separate units: overs, then balls.
The run rate and bowling economy calculators already accept cricket overs notation. Enter 12.4 in their overs fields, rather than the rounded decimal value 12.67.
A quick check for the ball digit
The jump from .5 to the next whole over is often where a spreadsheet or mental calculation goes wrong. These rows show the final few balls of an over alongside common innings counts. Decimal values are rounded to match this converter’s display.
| Cricket overs | Total balls | Decimal overs |
|---|---|---|
| 0.1 | 1 | 0.17 |
| 0.5 | 5 | 0.83 |
| 1.0 | 6 | 1.00 |
| 7.2 | 44 | 7.33 |
| 7.3 | 45 | 7.50 |
| 7.4 | 46 | 7.67 |
| 7.5 | 47 | 7.83 |
| 8.0 | 48 | 8.00 |
| 12.4 | 76 | 12.67 |
| 20.0 | 120 | 20.00 |
| 50.0 | 300 | 50.00 |
Whole overs can be entered without the point: 8 and 8.0 both convert to 48 balls. For a partial over, write one ball digit only. Values such as 7.6, 7.8 or 7.25 are not accepted by this form.
Find how much of the innings is left
Suppose an innings is scheduled for 20 overs and the scorecard shows 16.5 completed. The allocation is 120 balls; the completed portion is 16 × 6 + 5 = 101 balls. There are 19 balls left, which is 3.1 overs. Ordinary subtraction, 20 − 16.5 = 3.5, would leave you four balls out.
| Step | Working |
|---|---|
| Revised total allocation | 18 overs = 108 balls |
| Already faced | 11.4 overs = 70 balls |
| Still available | 108 − 70 = 38 balls |
| Write back as overs | 38 = 6 × 6 + 2, so 6.2 overs |
Use the revised total allocation if officials have shortened the innings. Convert the allocation and the completed count separately, then subtract the ball totals. The single input above does not know the innings limit and does not perform that subtraction automatically.
The result’s “Balls Remaining in Over” is a smaller measure. At 16.5 it says one ball is needed to finish that over. It is not saying that only one ball remains in a 20-over innings. At a whole-over boundary, its next-over message applies only if play is due to continue.
Add bowling spells without losing a ball
Imagine a bowler delivers 3.4 overs in one spell and 2.5 in a later spell. The first spell is 22 balls and the second is 17. Together they make 39 balls, or 6.3 overs. Adding 3.4 + 2.5 as decimal numbers gives 5.9, which is not a valid completed-over count.
The same approach works when comparing two scorebook checkpoints. From 8.5 to 13.2, the count moves from 53 balls to 80. The passage lasted 27 balls, or 4.3 overs. Convert both checkpoints to balls before finding the difference; do not subtract the point-separated labels directly.
For a spreadsheet, keep a whole-number balls column for addition, subtraction and rate formulas. Use a separate display column for overs and balls. This also avoids spreadsheet formatting turning an input such as 12.4 into 12.40, which hides whether the original field was cricket notation or a decimal measurement.
Turn a ball count back into overs
Divide the ball total by six and keep the quotient and remainder separate. For 101 balls, 16 complete groups of six use 96 balls and leave five. Write the answer as 16.5 overs. Dividing on a normal calculator gives 16.833…, which is the decimal-over value instead.
A useful self-check is to reverse your answer: 16 × 6 + 5 returns 101. For 120 balls, there is no remainder, so the notation is 20.0. This reverse method is explained here for manual use; the form at the top expects an overs entry, not a ball total.
Avoid converting back from a rounded decimal if you still have the original ball count. A display such as 0.17 is an approximation of one-sixth of an over. Retaining the integer ball count keeps repeated calculations exact.
Counted balls are not always physical deliveries
In a normal six-ball over, a wide or no-ball does not advance the counted-ball total. Six valid deliveries plus two wides can therefore involve eight physical deliveries while adding only one over to the scorecard. Extras are runs, not a substitute for a delivery log: five wide runs do not necessarily mean five separate wide deliveries.
Dead-ball situations also need the scorer’s record: a dead-ball call does not invariably mean the delivery is excluded. Use the umpire’s decision and the recorded count. The converter performs the six-ball arithmetic; it cannot reconstruct what happened to each delivery.
An umpire’s miscount is another limit. MCC Law 17 says the over as counted by the umpire stands. If an official over contained a different number of valid balls, multiplying the displayed overs by six cannot recover that exception. Check the ball-by-ball record when an exact delivery audit is needed.
Questions about overs and balls
Why does the input stop at .5 rather than .9?
In a standard six-ball over, the sixth valid ball completes the over. After 8.5, the next valid ball takes the completed count to 9.0. Enter 9 or 9.0, not 8.6. This converter expects a completed-over count, not the label attached to an individual delivery in commentary.
Can I enter zero overs?
Zero overs represents zero counted balls, but this form currently requires a value greater than zero. Enter 0.1 for the first valid ball. A blank field means no entry and does not produce a result.
Can I paste 12.40 or 12.67 from a spreadsheet?
No. The input accepts a whole over count or a point followed by one digit from 0 to 5. If a spreadsheet changed the formatting, check the original unit before editing the value. In particular, 12.67 rounded decimal overs is not valid scorecard notation and should not be pasted into this field.
Does Total Balls mean every delivery the bowler sent down?
No. It is the six-ball conversion of the recorded overs. Wides and no-balls do not advance the over count, so the number of physical deliveries may be higher. Use the delivery log if you need workload including those balls.
Why does a whole-over result say six balls in the next over?
At 8.0 the eighth over is complete. There are no balls left to finish it; a new over, if one is to be played, begins with six. The message does not mean the innings has another over available. This tool has no innings-limit input.
Can the result be used as a batter’s balls faced?
Do not replace a batter’s recorded balls faced with the team’s converted overs. The innings count includes deliveries faced by different players, and balls-faced records use their own scoring conventions. Take the individual BF figure from the scorecard for a batting strike-rate calculation.
Can I convert balls back to overs with this form?
The form takes overs as its input. To reverse the calculation by hand, divide the ball total by six: the whole-number quotient is completed overs and the remainder is the ball digit. For 101 balls, the quotient is 16 and the remainder is 5, giving 16.5 overs.
Does this work for The Hundred or older scorebooks?
Only use it when the recorded overs contain six counted balls each. The Hundred uses a 100-ball innings with five- or ten-ball bowling sequences, so its counters are not interchangeable with this notation. For older scorebooks, check the over length used in that match before converting.
Method, sources and corrections
Prepared by CricketCals. Examples are invented to show the conversion, rather than taken from particular matches. The tool multiplies whole overs by six, adds the ball digit and displays decimal overs to two places. It assumes a standard six-ball count and does not change the match scorebook.
The scoring basis is MCC Law 17: The over. See also Law 20: Dead ball and Law 22: Wide ball. For the separate 100-ball format, read The Hundred’s competition rules.
Conversions run in your browser. See the privacy policy for advertising and other site data practices. If a conversion looks wrong, send the input and expected ball total through the contact page; include whether your source used cricket notation or decimal overs.